Here this is very...

[Aceix]

Why does the function func throws exceptions whiles it is not supposed to.?. PLS explain...

Code:

//exceptions specifications
#include <iostream>

using namespace std;

int func(char& a) throw()
{
    try
    {
        try
        {
            if(a>='a' && a<='z'){
                try
                {
                    throw a;
                }
                catch(char e)
                {
                    cout<<"Char catch/handler caught "<<e;
                }
            }
            else
                throw a;
        }

        catch(...)
        {
            cout<<"Passing over to the external handler...\n\n";
            throw;
        }
    }
    catch(char e)
    {
        cout<<"Caught "<<e;
    }
    catch(...)
    {
        cout<<"Default handler caught the throw.";
    }
}


int main()
{
    char x;

    cout<<"Enter a character: ";
    cin>>x;
    func(x);
    cin.ignore();
    cin.get();
}

[Moschops]

What exception does it throw that you think it shouldn't?

[Shock Bolt]

Why do you have two try statements at the top of the function?

[Disch]

The only way I see that func() could be throwing an exception is if your char e catch block was throwing (so that cout statement). But that is extremely unlikely to happen.

+1 Moschops. What makes you think that function is throwing an exception?


EDIT:

Also, @Shock Bolt: he has two exception handlers, hence the 2 try blocks. The first one catches and rethrows to the 2nd one.

[Aceix]

_@Moschops

all exceptions

[zb0S216C]

The function shouldn't throw anything. Also, the throw() specifier is redundant, since the compiler cannot ensure the function will not throw an exception during run-time. In C++11, there's the noexcept() specifier which attends to this issue.

_Wazzak

[Aceix]

Thanks Framework.
So can I use it in my code?

[zb0S216C]

Use what? throw()? You can, but it would be pointless. If you're talking about noexcept(), then I recommend that you do.

_Wazzak

[Aceix]

Thanks - noexcept();