C++ statement that prints yes if digit in string

[raines883]

Write a c++ statement that print's "yes" if there is a digit in the variable sport3. I'm trying to find the correct string command to do this an easy way.

[vlad from moscow]

The "correct command" is the standard algorithm std::any_of.:)

[raines883]

I was looking through the string references to try to find one of those. I found isgidit() but don't think that will work in this case. That's why I was wondering if there was something like isdigit() in the string reference that would let me be able to to that.

[MrHutch]

Vlad's way is fine.

If you're wanting to use isdigit() then that's fine too. You'd just have to loop through each character of the string and pass each character into isdigit().

You could use some sort of boolean flag to highlight whether or not you've found a digit.

[raines883]

So something like:

string sport3 = "Baseball2day";
bool digit = false;
    while(digit)
        {
            isdigit(sport3);
        }

Of course that wouldn't work so how would I go about stepping through each char?

[Fransje]

for ( int i = 0; i < sport3.length(); i++ ) {
    if ( isdigit( sport3[ i ] ) {
        return digitDetected;
    }
}

Something like this

[raines883]

Would you still do the sport3[ i ] since its not an array but just a string?

[Moschops]

Look up the string object. The [] operator exists for it so that it works like an array.

[raines883]

Well you were right about the [] so there's something new you learn. Got it working going off of Fransje's code so thanks for that. Instead of bool I just had it cout if there was a digit. Thanks for the help.