How do you display the number of iterations

How do you display the number of iterations it takes to find a number that the user would input into the binary search?



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#include <iostream>
#include <cmath>
#include <ctime>
#include <iterator>
using namespace std;
int selectionSort(int [], int);
int binarySearch(int[], int, int);


int main()
{
srand (time_t(NULL));
int narray[100];
for (int i=0; i<100; i++)
{
	narray[i]=rand()%999;
} 

	int i, moves;
	moves = selectionSort(narray, 100);

	cout << "The sorted list, in ascending order is: \n";
	for (i=0; i < 100; i++)
		cout << " " << narray[i];
	cout << endl << moves << " moves were made to sort this list. \n";
	int item, location,iterations;
	cout<<"Enter the number you wish to find:";
	cin>> item;

	location=binarySearch(narray, 100, item);
	iterations=selectionSort(narray, 100);
	if (location > -1)
		cout << "The number was found at index location " << location << " after " << iterations << " iterations."<<endl;
	else
		cout <<"the item was not found in the array\n";
	return 0;
}
int selectionSort(int num[], int numel)
{
	int i, j, min, minidx, temp, moves=0;

	for (i=0; i<(numel-1); i++)
	{
		min = num[i];
		minidx=i;
		for(j = i + 1; j < numel; j++)
		{
			if (num[j] < min)
			{
				min = num[j];
			minidx = j;
		}
		}

		if (min < num[i])
		{
			temp = num[i];
			num[i] = min;
			num[minidx] = temp;
			moves++;
		}
	}

	return moves;
}
int binarySearch(int list[], int size, int key){
	int left, right, midpoint;
	left=0;
	right=size -1;
	while (left <= right) {
		midpoint = (int) ((left + right) / 2);
		if (key == list[midpoint]) {
			return midpoint;
		}
		else if (key > list[midpoint])
			left = midpoint + 1;
		else
			right = midpoint - 1;
	}
	return -1;
}
put this outside any while, if, for loop condition.
int counter =0;
Line 19 would be my recommendation.

Every time the user inputs something you want to count
counter++;


Show Total
cout << "Your counter = " << counter << endl;
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