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pass by reference and pass and return

metulburr (585)
What is the difference between a function passing by reference and a function passing the variable and return it to the original variable. It seems to do the same?

This is the example code i was testing it on:

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#include <iostream>
using namespace std;
void passByValue(int var);
void passByRef(int *var);
int passAndReturn(int var);

int main(){
	int a = 13;
	int b = 13;
	
	cout << a << endl;
	cout << b << endl <<endl;
	
	passByValue(a);
	
	passByRef(&b);
	
	cout << a << endl;
	cout << b << endl;
	
	int c = 14;
	cout << c << endl;
	cout << &c << endl;
	c = passAndReturn(c);
	cout << c << endl;
	cout << &c << endl;
	
}
	
//pass by value //pass a copy of variable
void passByValue(int var){
	var = 99;
}

//pass by reference //pass in variable 's address, direct access
void passByRef(int *var){
	*var = 66; //change original value
}

int passAndReturn(int var){
	var = 1;
	return var;
}
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