pass by reference and pass and return

[metulburr]

What is the difference between a function passing by reference and a function passing the variable and return it to the original variable. It seems to do the same?

This is the example code i was testing it on:

#include <iostream>
using namespace std;
void passByValue(int var);
void passByRef(int *var);
int passAndReturn(int var);

int main(){
	int a = 13;
	int b = 13;
	
	cout << a << endl;
	cout << b << endl <<endl;
	
	passByValue(a);
	
	passByRef(&b);
	
	cout << a << endl;
	cout << b << endl;
	
	int c = 14;
	cout << c << endl;
	cout << &c << endl;
	c = passAndReturn(c);
	cout << c << endl;
	cout << &c << endl;
	
}
	
//pass by value //pass a copy of variable
void passByValue(int var){
	var = 99;
}

//pass by reference //pass in variable 's address, direct access
void passByRef(int *var){
	*var = 66; //change original value
}

int passAndReturn(int var){
	var = 1;
	return var;
}

[cire]

You don't actually pass by reference anywhere in your code.

Useful links:
http://www.parashift.com/c++-faq-lite/references.html
http://stackoverflow.com/questions/1647373/difference-between-pass-by-reference-and?rq=1
http://stackoverflow.com/questions/410593/pass-by-reference-value-in-c