How to exit program immediately if an exception occurs (without executing the rest of the statements)

[ghantauke]

try
{
	cin >> foo;
}
catch ( exception& e )
{
	cerr << "Exception occured." << e.what() << endl;
	return(0);
}

cout << "Should not output this";

I receive the "Should not output this" output even when exception occurs in the cin >> foo statement.
Why doesn't return(0) work as I'm assuming it to work and what's the right way of doing it?

[Felicia123]

insert

exit(1);

inside your

catch

[Peter87]

If line 4 throws an exception line 12 should never run. Are you sure it throws an exception?

[deckeresq]

Peter87 is right, it looks like an exception isn't ever being thrown.

For debugging purposes, try adding in a

cout << foo;

right after you try to read foo in. This will let you know if an error is occurring or if your program is reading in something that you aren't expecting/don't want it to.

In what context are you putting cin in a try block, by the way? That might help us figure out a better way to set this up.

[SamuelAdams]

// exceptions
#include <iostream>
using namespace std;
int foo=0;

int main () 
{
try
{
	cout << ":";
	cin >> foo;
	cout << foo << endl;
	throw 2;
}
catch (int e)
{
	cerr << "Exception occured." << e << endl;
	return(0);
}

cout << "Should not output this";
}

Reference : http://www.cplusplus.com/doc/tutorial/exceptions/

[Cubbi]

@ghantauke
If you were meaning to catch exeptions thrown by cin >> foo, you need to enable them first, try

#include <iostream>
using namespace std;

int main ()
{
    cin.exceptions(ios::failbit);
    int foo;
    try
    {
        cin >> foo;
    }
    catch (const exception& e)
    {
        cerr << "Exception occured." << e.what() << '\n';
        return 0;
    }
    cout << "An integer was successfully parsed\n";
}  

demo: http://ideone.com/DlYomT