answer this?
If the size of integer is 4bytes, What will be the output of the program?
#include<stdio.h>
int main()
{
int arr[]={12,13,14,15,16};
printf(“%d,%d,%d\n”,sizeof(arr),sizeof(arr[]),sizeof(arr[0]));
return 0;
}
A.10,2,4 B.20,4,4 C. 16,2,2 D.20,2,2
#include<stdio.h>
int main()
{
int arr[]={12,13,14,15,16};
printf(“%d,%d,%d\n”,sizeof(arr),sizeof(arr[]),sizeof(arr[0]));
return 0;
}
A.10,2,4 B.20,4,4 C. 16,2,2 D.20,2,2
n/a, the code won't compile.
EDIT:
Getting around the compiler error, you should still be able to figure out the answer the teacher expects because of the other two sizeofs()
EDIT:
Getting around the compiler error, you should still be able to figure out the answer the teacher expects because of the other two sizeofs()
Last edited on
I have to check by the C++ Standard but I think that a compilation error shall be issuied.
In my opinion the problem that arrays are not implicitly converted to pointers in the sizeof operator. So this expression sizeof( arr[] ) is incorrect because arr[] is an incomplete type.
But one more I have to check this by the C++ Standard.
In my opinion the problem that arrays are not implicitly converted to pointers in the sizeof operator. So this expression sizeof( arr[] ) is incorrect because arr[] is an incomplete type.
But one more I have to check this by the C++ Standard.
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