GCC-Ubuntu: How come this code works?

[SameerThigale]

#include <stdio.h>

int main(void)
{
	int i[0];
	i[0]=9;
	printf("%i\n", i[0]);
	return 0;
}

This code compiles as well as runs correctly on gcc. How come?
Please help! Thank you dears!

[JLBorges]

> This code compiles

Does it?

source.c:5:8: error: ISO C forbids zero-size array 'i' [-pedantic]

http://liveworkspace.org/code/2uZeub$0

It is not valid C++11 either.

[SameerThigale]

I'm using GCC 4.6.3
And it compiles with it :(

[JLBorges]

Demand conformance with the standard, and gcc would generate an error.
> g++ -std=c89 -pedantic-errors -c my_ill_formed_program.c

[vlad from moscow]

Change int i[0] to int i[1] and the code will work :)

#include <stdio.h>

int main(void)
{
	int i[1];
	i[0]=9;
	printf("%i\n", i[0]);
	return 0;
}