*Flip For Loop Output

[bigapples]

I'm back again, thanks for the help last time cplusplus. This little code has me stumped.

int i,j,n=0,odd_number;

cout << "Enter only a Odd number: " <<endl;
cin>>odd_number;

   if (odd_number % 2 == 1)
       for(i = 0; i < odd_number; i++)
	{
	   for(j = i; j > 0; j--) 
	     cout<<" "; // displays the space before +
	   for(j = i; j < odd_number - i ; j++) 
	     cout<<"+"; // displays the + 
	     cout<<"\n";
	}
   else 
	{
             cout << "You did not enter a Odd number!"<<endl;
	}

Gives me this. But I need to flip the pyramid so that it starts with 1 + on top and ends with <user input> on bottom; in this case 11

Enter only a Odd number:
11
+++++++++++
 +++++++++
  +++++++
   +++++
    +++
     +





Press any key to continue . . .

[MiiNiPaa]

line 7: for(i = odd_number - 1; i >=0; --i)

[bigapples]

Thank you so much!!