Arrays

[mrantonresch]

I have created a program that the user enters in 3 digits and the program reverses the digits and prints it out.
Except in my reverse function it seems to only send out the last of the 3 digits (i.e if you were to enter 1, 2, 3) it will only printout 3,3,3.
How do I make it print out all the digits?

#include <iostream>
using namespace std;

int reverse (int a[])
{
	int n;
	int b [3];
	int i;
	i = 0;
	for(n=2; n>-1; n--)
	{
		b[i] = a[n];
		i++;
	}
	
	return *b;
}

int main ()
{
	int e [3];
	int r;
	int n;

	cout << "Please enter 3 numbers: " << endl;
	for(n=0; n<3; n++)
	{
		cin >> e[n];
	}

	r = reverse(e);

	cout << "The 3 numbers reversed are: " << endl;
	for(n=0; n<3; n++)
	{
		cout << r << endl;
	}
} 

[whitenite1]

@mrantonresch

Here's one way. I'm sure others will show you more elegant answers, but this is how I would do it..

// Reverse Digits.cpp : main project file.
#include <iostream>
using namespace std;

int reverse (int e[])
{
	int n;
	int b [3];
	int i;
	i = 0;
	for(n=0; n<3; n++)
	{
		b[n] = e[n];
	}
	
	for(n=0; n<3; n++)
	{
		e[n] = b[2-n];
	}
	return *e;
}

int main ()
{
	int e [3];
	int n;

	cout << "Please enter 3 numbers: " << endl;
	for(n=0; n<3; n++)
	{
		cin >> e[n];
	}

	reverse(e);

	cout << "The 3 numbers reversed are: " << endl;
	for(n=0; n<3; n++)
	{
		cout << e[n] << endl;
	}
} 

[mrantonresch]

Thank you so much, I finally understand it, ive been stuck for 2 days now.

[cire]

In the original code, you return only the first element of the local b array, which is why you output the same number 3 times

For kicks:

#include <iostream>

void do_it(int n)
{
    if ( n == 0 )
    {
        std::cout << "The numbers are\n" ;
        return ;
    }

    int input ;
    std::cin >> input ;

    do_it(n-1) ;

    std::cout << input << ' ' ;
}

int main()
{
    std::cout << "Please enter 3 numbers.\n" ;
    do_it(3) ;
    std::cout << std::endl ;
}