Solved...Converting string to float with sstream issue

[Exempt]

The fix was to use
cout << fixed << gained << endl;

I'm using streamstring to convert a string to a float like this... I'm grabbing the number from between " by " and " to " which does work fine in my tests.

                        f1 = line.find(" by ") + 4;
                        f2 = line.find(" to ");
                        if(f1 != string::npos && f2 != string::npos)
                        {
                            output.append(line, f1, (f2-f1));
                            stringstream strStream(output);
                            strStream >> gained;
                            cout << gained << endl;
                            //output += " ";
                        }

The issue is anytime a exp gain is smaller then 000100 (ex. 000053) it will make the float = 5.3e-005.

Mind 1.3e-005
Repairing 0.000683
Mind logic 1.5e-005
Miscellaneous items 5.3e-005
Miscellaneous items 5.3e-005
Miscellaneous items 5.3e-005

Actual text file contains...

[11:00:42] Mind increased by 0.000013 to 28.273088
[11:00:44] Repairing increased by 0.000683 to 36.72822
[11:00:45] Mind logic increased by 0.000015 to 33.352554
[11:00:46] Miscellaneous items increased by 0.000053 to 59.788166
[11:00:48] Miscellaneous items increased by 0.000053 to 59.788219
[11:00:49] Miscellaneous items increased by 0.000053 to 59.788273

Edit: I also tried using sprintf..
sprintf((char*)output.c_str(), "%f", gained);
It's output is always like..

Miscellaneous items 8.17609e-027
Repairing 8.17609e-027
Mind logic 8.17609e-027

and...

double gained = ::atof(output.c_str()); This has the same result as sstream

[jlb]

You can use some of the iomanipulators to format your number the way you desire. Look for the setprecison() member function as well as the std::ios format fields.

http://www.cplusplus.com/reference/iomanip/
http://www.cplusplus.com/reference/ios/ios_base/setf/

[Chervil]

What exactly is the question?
If we take this line:
[11:00:46] Miscellaneous items increased by 0.000053 to 59.788166
The string output (assuming it is empty at the start), will contain "0.000053"

If that is converted to type double, then 5.3e-05 is a correct representation of the number.

If you prefer not to use scientific notation, then instead of
cout << gained << endl;
use
cout << fixed << gained << endl;

[Exempt]

Ah, I should have mentioned I tried doing that aswell but the issue I had was the floats can change alot. x.x, x.xx, x.xxx... all the way to 6 decimals.

Edit: Chervil that did what I was needing... How on earth did you even find out about << fixed... always something little. Thanks a bunch for the replies.

[Chervil]

How on earth did you even find out about << fixed

I looked on the reference page here:
http://www.cplusplus.com/reference/ostream/ostream/operator%3C%3C/