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### help while loop

 ``12345678910111213141516171819202122`` ``````/ int Num = 18; cout << " Multiples of 9 from 27 to 81:\n"; while ( num <= 81 ) { Num = Num + 9; cout << Num << " "; num++; } int n = 1; int NUM = 0; cout << " 3 raised to the power of n + 1 where n is 1 to 10\n"; while ( n <= 10) { 3 * pow(n) + 1 = NUM; cout << NUM << " "; NUM++; } return 0; }``````

my program should produce the output

Multiples of 9 from 27 to 81:27 36 45 54 63 72 81
3 raised to the power of n + 1 where n is 1 to 10: 4 10 28 82 244 730 2188 6562 19684 59050

where did I go wrong?
Right then, now that I slapped myself awake.

I assume the pow you are using is the one included in cmath, it takes 2 arguments, in this case 3.0 and n+1.

You're also mixing up math with c++, NUM should be assigned the equation:
`NUM = pow(3.0, n+1); `

Finally you're incrementing NUM in the while loop, this also means that n is never changed and you'll have an infinite loop, so change that to n++ instead.
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 ``12345678910`` ``````int n = 1; int sum = 0; cout << " 3n=1 where n is 1 to 10\n"; while ( n <= 10) { sum = pow(3.0, n+1); cout << sum << " "; n++; } ``````

the math is still not right for the last output?
anyone help???????????????
 ``123456789`` ``````int n = 1; int sum = 0; cout << " 3n=1 where n is 1 to 10\n"; while ( n <= 10) { sum += pow(3.0, n+1); //note + cout << sum << " "; // maybe endl would make it look better? n++; }``````
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 ``123456789`` ``````int n = 1; int sum = 0; cout << " 3n=1 where n is 1 to 10\n"; while ( n <= 10) { sum = pow(3.0 , n + 1); cout << sum << " "; n++; }``````

still my math is wrong I need it to ouput this: 3 raised to the power of n + 1 where n is 1 to 10: 4 10 28 82 244 730 2188 6562 19684 59050
 ``123456789`` ``````int n = 1; int sum = 0; cout << " 3n=1 where n is 1 to 10\n"; while ( n <= 10) { sum = pow(3,n)+1; cout << sum << " "; n++; }``````

output is correct with this one, but i dont know why it is impressed that way...

true table of power 3 is: 3, 9, 27, 81.....
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That fixed it thanks so much!!!!!!
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