simple C to MIPS convertion
I'm having some trouble understanding MIPS
it should be simple
assuming i,j,k,f are stored in registers $s0, $s1, $s2, $s3
f= i-j-k
and why
also if someone could show me what SLL $s0, $s1, 2 should be in hexadecimal, I'd be grateful
I have an answer for it but I don't think it's right
it should be simple
assuming i,j,k,f are stored in registers $s0, $s1, $s2, $s3
f= i-j-k
and why
also if someone could show me what SLL $s0, $s1, 2 should be in hexadecimal, I'd be grateful
I have an answer for it but I don't think it's right
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