Why is it giving me error? (Pointer array)

[Tiger58]

I am confused as to why it gives error when I try to use a pointer array like this:

//Don't mind the whole class nonsense
#include <iostream>
#include <string>
#include "Fish.h"
using namespace std;

void inputData(const int *const, Fishing*);

int main()
{
	Fishing *fishData;
	int fishnum,
		*pnum=&fishnum,
		option;

	cout<<"Enter the number of fish caught: ";
	cin>>*pnum;
	while(*pnum<0)
	{
		cout<<"ERROR. Please enter a positive value: ";
		cin>>*pnum;
	}

	fishData=new Fishing[fishnum];

        inputData(pnum,fishData);
}

//Gives error if I don't include the [] after "data" pointer array
void inputData(const int *const num, Fishing *data)
{
	string strVar;
	double doubVar;

	for(int i=0;i<(*num);i++)
	{
		cout<<"Enter data for fish #"<<(i+1)<<": "<<endl;
		cout<<"Type: ";
		cin>>strVar;
                //Giving me error here, fixes when I add [] to the top of function
		data[i]->setFishType(strVar);

	}
}

Yet the same thing works just fine here:

#include <iostream>
#include <cstdlib>
using namespace std;

void displayAll(const int *const, int);

int main()
{
	const int NUM=5;
	int num[NUM]={1,2,3,4,5};
	int *numpt=num;

	displayAll(num,NUM);

}

//No [] on the pointer array yet it runs just fine
void displayAll(const int *const arr, int NUM)
{
	for(int i=0;i<NUM;i++)
	{
		cout<<arr[i]<<endl;
	}
}

[MiiNiPaa]

data[i] equivalent to *(data+i): pointer already dereferenced, so you should use operator "." instead of "->"

[Tiger58]

Nice thank you