calling methods and constructor class

[Eliza0210]

I didn't understand how this code works.

#include <iostream>
using namespace std;

class abcd {
public:
static int a;
int b;
abcd(int x) {
b=x;
a=b+1;
}
};

int abcd::a=0;  
int main(void) {
abcd b1(5);
abcd b2(12);
cout << "b1.a is " << b1.a << endl;
cout << "b1.b is " << b1.b << endl;
cout << "b2.a is " << b2.a << endl;
cout << "b2.b is " << b2.b << endl;
}

When it says abcd b1(5);
I literally insert 5 into
abcd(int x){
b=x;
a=b+1;
}
so b =5
and a=6
But I don't think it works like that.
Somebody please explain me how it works.

[maeriden]

It works like that.
The value you pass to the function will be referred to as 'x' inside it. In this case you passed 5 so wherever you write 'x' it's like like writing 5. If you wrote abcd b1(7); it would have been like writing 7 instad of 'x' everywhere (not EXACTLY the same, but pretty much the same).

[Eliza0210]

Thanks maeriden.
Also can you please explain me how b1.a and b1.b works?
cout << "b1.a is " << b1.a << endl;
cout << "b1.b is " << b1.b << endl;