Problem with analysing string

[Constipator]

Greetings,

I've been studying programming from time to time and decided to make a text adventure, to practice what I already know. However, I have bumped into a problem with analysing a string that is determined by user input:

for( pos = i.begin(); pos != i.end() || pos != i.find( " " ); ++pos){
         iCheck += *pos;

This was supposed to look trough the string and put the first word into a seperate string:
The loop ends when the string is only one word long
pos != i.end()
or is supposed to end when it encounter a space in the string
|| pos != i.find( " " )
However, when trying to run my program I get the following error:

error: no match for 'operator!=' in 'pos != (&i)->std::basic_string<_CharT, _Traits, _Alloc>::find [with _CharT = char, _Traits = std::char_traits<char>, _Alloc = std::allocator<char>](((const char*)" "), 0u)'

[vlad from moscow]

I have not understood what you are trying to do but as for the error then pos has type std::string::iterator while the return value of member function find has type std::string::size_type. There is no such conversion function that converts an object of the first type into an object of the second type. So the compiler issued the error.

[Zaita]

tbh, I'd just use boost split to do this for you:

    vector<string> split_words;
    boost::split(split_words, my_string_to_split, boost::is_any_of(" "));

.find() returns size_type and .begin()/.end() return an iterator. They are not compatible types to compare.