How to print first and last day of month Only

[Melicalol]

Hello all,

I am new to the forums so let me know if this code is not beginner level and I will post it somewhere else.

I am also new to programming, so I am struggling a bit with this code.
I need to make a code to print the first day of the month and last, for the year and month the user inputs.

example
cout "please type a month and year "
if user types 04 2013

The code I write has to print

1 monday
30 tuesday

Only!

I can make a code to print first day of the month, or all days of the month, What I am struggling with is printing both First and Last. So If anyone experienced enough that can give me a tip on how to print Last day of the month that would be really helpful.

Reason for this is because, I have to make a GUI calender and other dates are irrelevant with my GUI code.


Below is a code exactly similar to what I wrote mine like, I will post mine later( very similar) when I am on my desktop.


---edit: P.S new to typing in English too apparently Awkward "I" sentence starter.
xD

#include "std_lib_facilities_3.h"



bool LeapYear (int year)

// "year" must be between 1900 and 2999.
// Returns true if "year" is a leap year.

{
// true, if year is divisible by 4, and ...
// ... either not divisible by 100, or divisible by 400. 

return (year % 4 == 0 &&
(year % 100 != 0 || year % 400 == 0));
}

//**************************************

const int daysInMonth[12] = {

31, 28, 31, 30, 31, 30,
31, 31, 30, 31, 30, 31
};

// Days from the beginning of the year
// to the beginning of the month:

const int daysToMonth[12] = {
0, 31, 59, 90, 120, 151,
181, 212, 243, 273, 304, 334
};

const char *dayName[7] = {
"Sunday",
"Monday",
"Tuesday",
"Wednesday",
"Thursday",
"Friday",
"Saturday"   // ** made constant " #"
};

const int DAY0 = 1; // Day of week for 01-01-1900 is Monday = 1.

//**************************************

bool ValidDate (int month, int day, int year)

// Returns true if month-day-year is a valid date between
//   01-01-1900 and 12-31-2999.

{
    bool valid = false;  // First assume the date is invalid.
    int days;

    // If year and month have valid values:
    if (year >= 1900 && year <= 2999 &&
                                month >= 1 && month <= 12) {

        // Get the number of days in this month from the table:
        days = daysInMonth[month-1]; // (-1, because the indices
                                     //   of an array start from 0.)

        // If February of a leap year -- increment the number
        //   of days in this month:
        if (month == 2 && LeapYear(year))
            days++;

        // Check that the given day is within the range.
        //   If so, set valid to true:
        if (day >= 1 && day <= days)
            valid = true;
    }

    return valid;
}


//**************************************

long DaysSince1900 (int month, int day, int year)

// Returns the number of days elapsed since 01-01-1900
// to month-day-year

{
long days;

// Calculate days to 01-01 of this year with correction for
// all the previous leap years:
if (year == 1900)
days = 0;
else
days = long(year - 1900) * 365
+ (year - 1901) / 4 // +1 for each 4th year
- (year - 1901) / 100 // -1 for each 100th year
+ (year - 1601) / 400; // +1 for each 400th year,
// starting at 2000

// Add days for previous months with correction for
// the current leap year:
days += daysToMonth[month-1];
if (LeapYear(year) && month > 2) days++;

// Add days since the beginning of the month:
days += day - 1;

return days;
}

//**************************************

int DayOfWeek (int month, int day, int year)

// Returns the day of the week for a given date:
// 0 -- Sunday, 1 -- Monday, etc.

{
return int((DAY0 + DaysSince1900(month, day, year)) % 7);
}

int main()



{


int month, day = 1, year, days, j;
int weekday;
cout << "Please enter a month and a year==> ";
cin >> month >> year;

if (!ValidDate(month, day, year)) {
cout << "*** Invalid date ***\n";
return 1;
}

if(month == 1) days = 31;
if(month == 2) days = 28;
if(month == 3) days = 31;
if(month == 4) days = 30;
if(month == 5) days = 31;
if(month == 6) days = 30;
if(month == 7) days = 31;
if(month == 8) days = 31;
if(month == 9) days = 30;
if(month == 10) days = 31;
if(month == 11) days = 30;
if(month == 12) days = 31;

for(j = 1; j <= days; j++)
{
cout << j << " ";

weekday = DayOfWeek(month, j, year);
if(weekday == 0) cout << "Sunday 0 ";
if(weekday == 1) cout << "Monday 1 ";
if(weekday == 2) cout << "Tuesday 2 ";
if(weekday == 3) cout << "Wednesday 3 ";
if(weekday == 4) cout << "Thursday 4 ";
if(weekday == 5) cout << "Friday 5 ";
if(weekday == 6) cout << "Saturday 6";

cout << endl;
}
keep_window_open("~");	// For some Windows(tm) setups
return 0;
}
	
	

[MiiNiPaa]

It is simple:
Instead of your loop you should output day of week for
DayOfWeek(month, 1, year) and DayOfWeek(month, days, year)

[Melicalol]

Hey thanks for the respond. :), and thanks for making it so clear!

[Melicalol]

" DayOfWeek(month, days, year)"

{


weekday = DayOfWeek(month, 1, year);
if(weekday == 0) cout << "Sunday 0 ";
if(weekday == 1) cout << "Monday 1 ";
if(weekday == 2) cout << "Tuesday 2 ";
if(weekday == 3) cout << "Wednesday 3 ";
if(weekday == 4) cout << "Thursday 4 ";
if(weekday == 5) cout << "Friday 5 ";
if(weekday == 6) cout << "Saturday 6";

cout << endl;
}

works prints first day of code.

 weekday = DayOfWeek(month, days, year);
if(weekday == 0) cout << "Sunday 0 ";
if(weekday == 1) cout << "Monday 1 ";
if(weekday == 2) cout << "Tuesday 2 ";
if(weekday == 3) cout << "Wednesday 3 ";
if(weekday == 4) cout << "Thursday 4 ";
if(weekday == 5) cout << "Friday 5 ";
if(weekday == 6) cout << "Saturday 6";

cout << endl;

Does not work? any idea what I am doing wrong?

*** Edit : It works, but what it lacks now it won't tell me what the last day is if its (28, 29, 30 or 31). Any idea how to fix that since i removed for loop with j?


2nd Edit: Nvm :) it works. Thanks