Extracting file name from path

[giorgik]

Hello everyone,
I have a string like this

const char *filename = "C:/Qt/progetti/worlds/fasr.world";

then I have a string like this

char *pathdir = "C:/Qt/progetti/worlds";

I would get this string: "worlds/fasr.world" how should I do ?

[ne555]

http://linux.die.net/man/3/basename

[KRAkatau]

Or, if you're using Qt:

QDir(pathdir).relativeFilePath(filename);

Although in this case your pathdir should be "C:/Qt/progetti".

[giorgik]

Thanks for the responses, but my problem is obtaining only the final part of the filename string, ie "worlds/fasr.world" ("worlds/" which is a part of path and "fasr.world" which is the name of the file)

[ne555]

std::string( basename(pathdir) ) + std::string("/") + std::string( basename(filename) );

[giorgik]

Thanks ne555

[cire]

Or you could use boost for a more portable solution. (The code is nearly the same.)

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#include <iostream> #include <boost/filesystem.hpp> namespace fs = boost::filesystem ; int main() { const char *filename = "C:/Qt/progetti/worlds/fasr.world"; char *pathdir = "C:/Qt/progetti/worlds"; std::cout << fs::basename(pathdir) + '/' + fs::basename(filename) + fs::extension(filename) << '\n' ; // Or: //fs::path path_with_name("C:/Qt/progetti/worlds/fasr.world") ; //fs::path base_path("C:/Qt/progetti/worlds") ; //std::cout << base_path.filename().string() + '/' + // path_with_name.filename().string() << '\n' ; }

worlds/fasr.world