Pointer to method problem

[sever]

Hi guys,

Could you please help me to correct this example code ?

---

#include <iostream>
#include <string>
#include <map>

class HiddenFunc
{
public:
   HiddenFunc();
   ~HiddenFunc();

   void execute();

private:
   int hello();

   std::map<std::string, int (HiddenFunc::*)()> funcs;
};

HiddenFunc::HiddenFunc()
{
   funcs["hello"] = &HiddenFunc::hello;
}

int
HiddenFunc::hello()
{
   return 10;
}

void
HiddenFunc::execute()
{
   std::cout
      << "Value : " << this->*funcs["hello"]() << std::endl; // wrong line (see below)
}

int main()
{
   HiddenFunc hidden_func;

   hidden_func.execute();

   return 0;
}

---

The compiler message is:

g++ hiddenfunc.cc -o hiddenfunc
hiddenfunc.cc: In member function ‘void HiddenFunc::execute()’:
hiddenfunc.cc:34:46: error: must use ‘.*’ or ‘->*’ to call pointer-to-member function in ‘((HiddenFunc*)this)->HiddenFunc::funcs.std::map<_Key, _Tp, _Compare, _Alloc>::operator[]<std::basic_string<char>, int (HiddenFunc::*)(), std::less<std::basic_string<char> >, std::allocator<std::pair<const std::basic_string<char>, int (HiddenFunc::*)()> > >((* & std::basic_string<char>(((const char*)"hello"), (*(const std::allocator<char>*)(& std::allocator<char>()))))) (...)’, e.g. ‘(... ->* ((HiddenFunc*)this)->HiddenFunc::funcs.std::map<_Key, _Tp, _Compare, _Alloc>::operator[]<std::basic_string<char>, int (HiddenFunc::*)(), std::less<std::basic_string<char> >, std::allocator<std::pair<const std::basic_string<char>, int (HiddenFunc::*)()> > >((* & std::basic_string<char>(((const char*)"hello"), (*(const std::allocator<char>*)(& std::allocator<char>())))))) (...)’
make: *** [hiddenfunc] Error 1

---

So, How should I call the method ??

Thanks,

[MiiNiPaa]

std::cout << "Value : " << (this->*funcs["hello"])() << std::endl;
There was operator precedence problem: function call operator has higher priority than member pointer dereference one. so your line was interpreted as this->*( funcs["hello"]() )

[sever]

That's it !!!... Thanks ;)