As I can order several test cases, while receiving data???????

[zionet]

PROBLEM
As I can order several test cases, while receiving data???????

MY PROBLEM
entrance
The entry contains the number you want to represent in binary.

exit
Enter in a line the minimum number of bits required to represent this number.

Examples of input

32
12
1

Output examples

6
4
1

MY BAD SOLUTION
# include <iostream>

using namespace std;

int main ()
{
long long int n, c;
cin >> n;
c = 0;
while (c + +, n> 1)
{
n = n / 2;
}
cout << c;
}

[28poGNh0]

The while statement does not accept a comma-separted list,mean that you cannot do while(,,,,,,) otherwise if you want to check various condition ,you can use some logical operators like && and || exp

while(condition||condition)

this another version of your program

# include <iostream>
using namespace std;

int main ()
{
    long long int n, c;
    cin >> n;
    c = 1;

    while (n>1)
    {
        n = n / 2;
        c++;
    }
    cout << c << endl;

    return 0;
}

[S G H]

His example is still valid.

while(c++, n>1)
evaluates to
while(1) { c++; if(!(n>1)) break; [...] }

What's wrong with your code @op?

[funprogrammer]

EssGeEich is right. Your code should work.

I compiled your code with some cout statement and verified it be working

int main ()
{
   int n, c;
   cout << "Enter the number" << endl;
   cin >> n;
   c = 0;
   
   while(c++, n> 1){
      n = n / 2;
   }
   cout << c << endl;
   return 0;
}

The output is

Enter the number
54
6
Press any key to continue . . .