I have made the previous problem simpler to get the answer and understand it completely.
The problem is that I want to write a C++ program that converts an ordinary text file into binary and then reads that binary file and converts it to text file so that this text file equals to first text file.
I have wrote this code for it.
string name1 = "first", name2 = "sec", name3 = "third";
int j = 0, k = 0;
ifstream ifs(name1.c_str()); // Here I want to read from the ordinary text file (name1).
ifs >> j; // Now j equals to 5 because name1 contains digit 5.
ofstream ofs(name2.c_str(), ios::binary);
ofs.write(as_bytes(j), sizeof(int)); // Here I want to write that j to name2 file in binary mode.
ifstream ifs1(name2.c_str(), ios::binary); // Here I want to read from that binary file (name2).
ifs.read(as_bytes(k), sizeof(int)); // Here I hope k becomes 5.
ofs1 << k; // Here I want to write that k to name3 file in ordinary text mode.
// Now I hope both name1 and name2 contain 5.
Now what the ofs.write(as_bytes(j), sizeof(int)); or ifs.read(as_bytes(k), sizeof(int)); exactly mean?
In practice, the file name1 contains digit 5 and its size is 1 byte. The name2 contains some character/sign like  and its size is 4 bytes and name3 contains digit 0 and its size is 1 byte, why?
I before have created the name1 file in ordinary text file mode
Please don't extent the issue by giving extra info and only think around this problem. I want just understand it.
I completely appreciate your responses.
My machine is Windows 7 32-bit. My compiler is MVS 2012. And if any more info is needed just tel me.
OK, some part of the problem is solved now. But still there is a problem.
Although the name1 and name3 contain same content (the solved part), but when the name1 is 97 name2 becomes the 'a' character. It seems like that the binary stream convert the ordinary text file's content (which is an integer digit, here 97) to its ASCII value and stores it into itself (here the 'a' character). Do you know why?