Square root Function

[moneysab]

I having trouble with the rational class
here is my assignment:

Add a square root function to the rational class. Have your program print the square root of any rational number.
I want to find the square root for numerator and denominator separatetly. divide the answer to get decimals and convert the decimal to fractions.
i got till geting the decimal but i want to convert it back to a simplified fraction

// finding greatest common factor
int gcd(int a, int b)
{
	if (b == 0)
		return a;
	else
		return gcd(b, a % b);
}

// square root
float root(float a, float b)
{
	float num = a;
	float den = b;
	float count1 = sqrt(num);
	float count2 = sqrt(den);
	float count3 = float(count1 / count2);
	return count3;
}


// Mutator
// simplifying rationals
void rational::simplify()
{
	int a1, a2, g;
	assert(bottom != 0);

	a1 = top;
	a2 = bottom;
	g = gcd(a1, a2);
	a1 = a1 / g;
	a2 = a2 / g;
	if (a2 < 0)
	{
		a2 = -a2;
		a1 = -a1;
	}
	top = a1;
	bottom = a2;
}

[moneysab]

Any help would be appreciated

[ats15]

Not sure you can achieve that. First an observation:

float root(int a,int b)
{
   return sqrt(1.0*a/b);
}

Since you are talking about fractions, I assume that a and b are integers (not floats). Also, no reason why you should use sqrt twice.

Now back to your problem: One very simple fraction is 2/1. You know that sqrt(2.0) is not a rational number. Please explain what you want to do in this case.
Also note that sqrt and float functions introduce rounding errors. Take for example 1/9. The square root is 1/3. But, since I use float, 1/3 is about 0.3333332, or some other number, slightly different than 1/3. Even if it's 0.333333, you will write this as 333333/1000000, which does not simplify to 1/3