how can i make function that can read an unsigned integer into a variable of type unsigned short int

[Noob Programmer]

How can i write a function that will read an "unsigned integer" into a variable of type "unsigned short int"?

 i can not use cin >> inside the function

.. so i am looking for atleast a hint!

[MatthewRock]

You mean this:

void funct(unsigned short int a)
{
  //code...
}

?
EDIT: Oh; I guess that you mean that you want user to input uint and you want to get it into variable. Well, you can use
cin.get(), <cstdio>'s functions...

[giblit]

I don't see the purpose of reading into an unsigned long then assigning it to an unsigned short.

i can not use cin >>

Is there a reason why you can't? You could always use std::getline then parse with a std::stringstream

[Noob Programmer]

this is an assignment i was given for school and that is the requirement. we have not gone over how to format this. i am trying to get ahead.

we always use

using namespace std.

but i am sure what you are saying would work giblit.

MatthewRock
this is the questionrequirements.

Designing the “ReadInt” function, it should be value returning and have a reference parameter. The function needs to process one character at a time from the input buffer and deal with it in a correct fashion. Once the number has been read in, then make sure the input buffer is empty, otherwise the loop in main may not work correct. I know this is not how the extraction works, but lets do it this way.

I do not get this at all..

#include <iostream>
#include <stdlib.h>

using namespace std;

int ReadInt (unsigned short int & N);
int main()

{
    int Error = 0;
    char Ch;
    long int Number = 0;
    long int N;
    
    cout << "Enter a Number --> ";
    cin >> Ch;
    
    if (!isdigit(Ch))
        {
            
        Error = 1;
        return Error;
            
        }
    while (isdigit(Ch))
        {
            
        Ch = Ch - '0';
            
            
        }
    if (Number > 65535)
        Error = 2;
    
    else
        
        N = Number;
    
    
    return Error;
    
        
}

[MatthewRock]

Boy, are they teaching you this code? It's a bit terrible.

Main should return int.
You don't need additional curly brackets inside main. It just limits scope, but you don't need that.
And your function, from what I see, should take reference to some integer, then extract number from stream, and assign the number to the reference.

What other ways of getting input, other then cin>>, have you learned? I guess it may either require you to look in book/web to find proper function, or use one you've already learned.
Either case, answer question(according to requirements): what C++ function allows you to read single character from stream?

[giblit]

I don't see it saying he can't use cin >> it just looks like they want to extract one character at a time. Via cin >> or cin.get reading into a character instead of integer then converting.

[Noob Programmer]

this is what i have been coming up with. i am not sure how to

write a function that will read an unsigned integer into a variable of type unsigned short int

#include <iostream>
#include <stdlib.h>

using namespace std;

int ReadInt (unsigned short int & N);
int main()

{
    int Error = 0;
    char Ch;
    long int Number = 0;
    long int N;
    
    cout << "Enter a Number --> ";
        cin >> Ch;
    
    if (!isdigit(Ch))
        {
            
        Error = 1;
        return Error;
            
        }
    while (isdigit(Ch))
        {
            
        Number = Ch - '0';
            
        }
    if (Number > 65535)
        Error = 2;
    
    else
        
        N = Number;
    
    
    return Error;
    
        
}

[giblit]

How about this.

1) Read in an int.
2) Check if the stream failed if so clear,ignore,display error and ask for a new input.
3) Check if the number is greater than or equal to zero and less than or equal to 65535
4) You now have a proper input.

pseudo code:

    do
        ask user to enter a number between 0 and 65535
        get user input
        check if it was valid input (!cin == failed)
        if(failed)
            clear, ignore, display error, and continue
    while number < 0 or number < 65535
    output the number

[Noob Programmer]

Here is my updated code

#include <iostream>
#include <stdlib.h>

using namespace std;

int ReadInt (unsigned short int & N);
int main()

{
    int Error = 0;
    char Ch;
    long int Number = 0, N = 0;
    
    cout << "Enter a Number --> ";
        cin >> Ch;
    
    if (!isdigit(Ch))
        {
            
        Error = 1;
        return Error;
            
        }
		while (isdigit(Ch))
        {

		Number = ((Ch - '0') + Number);
		Ch = cin.get();
		if (Number < 65535)
		Number = Number * 10;

        }

    if (Number > 65535)
        Error = 2;
    
    else
        
        N = Number;
    
    
    return Error;
    
        
}

[Noob Programmer]

how can i write a function that will read an unsigned integer into a variable of type unsigned short int?

[Noob Programmer]

how can i make it so when user enters 45678 that i will not get 456780?

also i am still working on function. i would greatly appreciate some feedback.

[giblit]

Is the assignment making you read in with characters instead of integers directly?

[Noob Programmer]

in the algorithm given there were characters used and it has thrown me off but

i have found how to make the number through a formula without using cin >>. 

the assignment however just shows that this needs to be done.

   write a function that will read an unsigned integer into a variable of type unsigned short int

i have made a loop to obtain the number through the characters.

		while (isdigit(Ch))
        {

		Number = ((Ch - '0') + Number);
		Ch = cin.get();
		if (Ch != '\n')
		Number = Number * 10;

        }

i need to write the function to do the actual problem. any feedback would be helpful.

[Noob Programmer]

Here is my updated code

#include <iostream>
#include <stdlib.h>

using namespace std;

int ReadInt (unsigned short int & N);
int main()

{
    int Error = 0;
    char Ch, Repeat;
    long int Number = 0, N = 0;
    
	do
	{
    
		cout << "\n\nEnter a Number --> ";
        cin >> Ch;
    
    if (!isdigit(Ch))
        {
            
        Error = 1;
        return Error;
            
        }
		while (isdigit(Ch))
        {

		Number = ((Ch - '0') + Number);
		Ch = cin.get();
		if (Ch != '\n')
		Number = Number * 10;


        }

    if (Number > 65535)
        Error = 2;

    
cout << "\n\nThe number inputed is " << Number ; 

cout << "\n\nError Code " << Error;

cout << "\n\n Would you like to use program again? Y or N?     ";
cin >> Repeat;
	}
	while (Repeat != 'n' || Repeat != 'N');
}

i need to split these into two functions.

ErrorCheck, and ReadInt.
i am just having trouble understanding the question of the function that needs to be made.

 write a function that will read an unsigned integer into a variable of type unsigned short int

[giblit]

It sounds like they want you to just read into an unsigned short.

So

unsigned short input;
std::cout << "Please enter an unsigned integer: ";
std::cin >> input;
//you can error check here if it failed to read. 

[Noob Programmer]

im not sure what you are telling me.
can you please elaborate.

[Noob Programmer]

I figured it out. thanks for trying to help.