Multiplying an array by 10

[zqMDizwU]

#include <iostream>
#include <cstdlib>

using namespace std;

int myArr[1];

int main(){

	for (int j = 0; j < 10000; j++)
	{
		myArr[j] = j + 1;
		cout << myArr[j] << "\n"; //or cout <<myArr[j] << " ";

		system("pause"); //or system("pause>nul"); 
	}
}

I am trying to initialize int x[] = {10, 100, 1000, 10000} into a loop and give me four different numbers for something. I was trying to get creative and just do myArr[j] = j * 10; with (int j = 1; j < 10000; j++) , but that doesn't work. It still gives me an output of 10 11 12... Does anybody know how to make an array punch through a loop and give me 10 Press any key to continue... 100 Press any key to continue... 1000 Press any key to continue... 10000 Press any key to continue.... I'm thinking I must set the for loop to < 10000.1 or < 10001 to output the final value in the array.

[cire]

myArr has a single element. The only valid index is 0.

int main()
{
    const unsigned myArrSize = 4 ;
    int myArr[myArrSize] ;

    const unsigned factor = 10 ;
    unsigned value = 1 ;
    for ( unsigned i=0; i<myArrSize; ++i )
        myArr[i] = (value *= factor) ;
}

[Smac89]

#include <iostream>
#include <limits>
using namespace std;

int main() {

    int myArr[8] = {10}; // only first value set to 10, rest are 0
    for (int j = 1; j < 8; j++)
    {
        myArr[j] = myArr[j - 1] * 10;
	cout << myArr[j] << "\n";
        
        cin.get();
        cin.ignore(numeric_limits<streamsize>::max(), '\n');
    }
    return 0;
}

Loop only goes to 8 because that is the max power of 10 you can represent with int type

[zqMDizwU]

Ok thank you so much Smac89! Job well done.