Double, int and float. See the differences.

[Gamytr]

I don't know where I made the mistake

#include <iostream>
using namespace std;

int main()

{

	int x,y;
	
	float a;
	double b;
	int c;
	
	cout<<"Birinci sayiyi giriniz:";
	cin>>x;
    cout<<"İkinci sayiyi giriniz:";
	cin>>y;

	a=x+y;
	b=x+y;
	c=x+y;

	cout<< "Float sum:" << a << endl;
	cout<< "Double sum:" << b << endl;
	cout<< "int sum:" << c << endl;
	
	return 0;
	
}

Ask :

x = 3;

y= 2.7;

write a code that get sum of these two numbers. write sum in three types of numbers double, int and float. See the differences.

[helios]

Both x and y are integers. Their sum will be a whole number regardless of whether the variable you store it in is an integer or not.

[Gamytr]

I understand, but do not fix

[giblit]

The only thing I see that is wrong is you input as int instead of float or double like assignment wants? When it is correct you will probably get 5 for int, then 5.6999999->5.7000001 with float and 5.6999999->5.700000000000001 with double.

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18

#include <iostream> #include <iomanip> int main() { //all inputs are with float type as if you had x and y as float. You could make them doubles also and cast that way int const a = 5.7f; //will implicitly cast to int which floors to 5 float const b = 5.7f; //no need to cast float is float double const c = 5.7f; //casts from float to double std::cout.setprecision(16); std::cout << "Int: " << a << std::endl; std::cout << "Float: " << b << std::endl; std::cout << "Double: " << c << std::endl; return 0; }

Int: 5 Float: 5.699999809265137 Double: 5.699999809265137

[Gamytr]

Thank you :))