How can shorten this code

[Angel2014fly]

How can shorten this code
I need to save 8739 blocks.
as shorten ofstream and classes.
as is a repeat, certain units read, you need to read
8739 blocks and save it,
here's the code:

#include <algorithm>
#include <fstream>
#include <iostream>
#include <string>
using namespace std;
class bufferx
{
public:
char buffer[ 1081 ]; 
	};
int main()
  {
bufferx me;
me.buffer[ 1081 ];
bufferx a;
a.buffer[ 1081 ];
char letter;
  ifstream file( "read.txt" );
   while (!file.eof())
           {
  fill_n( me.buffer, 1081, '\0' );	
  file.read( me.buffer, 1080 );
  string s( me.buffer );
ofstream binaryeik("block.txt",ios::out);
{
binaryeik<<me.buffer;
}
binaryeik.close();
 fill_n( a.buffer, 1081, '\0' );	
  file.read( a.buffer, 1080 );
  string si( me.buffer );
ofstream binaryeiki("block2.txt",ios::out);
{
binaryeiki<<a.buffer;
}
binaryeiki.close();
a:
ifstream binaryeikig("prodolziti.txt",ios::out);
letter = binaryeikig.get();
if(letter=='*') ;
else
  goto a;
   }
 file.close();
  return 0;
}

[SamuelAdams]

You can remove line 1 and 3 and save 300k bytes in the exe.