Pass Address of pointer to function

[novellof]

#include <iostream>
using namespace std;

void myfunc(int* ); // what do i put in these parameters to accept a mem loc of a pointer

int main ()
{
    int x = 5;
    
    int* ptr;
    
    myfunc(&ptr); ///This is how i want to pass the pointer to the function! 
    
    
    return 0;
}

void myfunc(int*)
{
    
}

SOLUTION:

#include <iostream>
using namespace std;

//Purpose to create a function that returns a pointer to a pointer
int** myfunc(int**);

int main ()
{
    int x = 5;
    int* ptr;
    int** ptrp;
    
    
    cout << &ptr << endl;
    
    ptrp = myfunc(&ptr);
    
    cout << endl;
    cout << ptrp << endl;

    
    
    cout << endl << endl;

    return 0;
}

int** myfunc(int** intpp)
{
    cout << intpp;
    
    return *&intpp;
}

[mutexe]

surely the memory address is just an integer?

[Computergeek01]

Face palm on Line 32, actually that whole function OP. Did you have an actual question here before your edit?

[novellof]

I found out how to do it before anybody replied so i figured I add the answer instead of delete the post.