Mixed expressions, loops and Formatted output

[map1987]

Hello,

I need some general guidance with the following problem:

1) ask the user to input a mathematical expression in the following format:
NUMBER Operator NUMBER Operator NUMBER
Example: 17 + 15 - 3
Example: 2 * 3 - 4

I am having trouble figuring out how to output the answer of the users equation. Is there a function that includes all math operators (+,-,/,*)? Would i need to write each possible scenario using if statements?

Any help is greatly appreciated.

[coder777]

Is there a function that includes all math operators (+,-,/,*)?

No. Write your own. Four operators are not too many.

Would i need to write each possible scenario using if statements?

No. You might use switch. It's not that difficult:

int do_operation(char op, int num1, int  num2)
{
  int result = 0;
  switch(op)
  {
  case '+':
  result = num1 + num2;
  break;
...
  }

  return result;
}
...
char op1, op2;
int num1, num2, num3;
...
cin >> num1 >> op1 >> num2 >> op2 >> num3;
cout << do_operation(op2, do_operation(op1, num1, num2), num3);

[billyb29]

If that is all you doing (number operator number operator number) it won't be too long, and the code coder777 gave you works fine. Make sure you consider operator precedence too.