Guessing Game

[Gbanawoman]

Hi guys! I'm trying to transform a code that has no bugs or anything, but I want to add on something. Here's the code:

#include <iostream>
#include <cstdlib>
#include <ctime>

int main(void) {
srand(time(NULL));

while(true) {
int number = rand() % 99 + 2;
int guess;
int tries = 0;
char answer;

while(true) {
std::cout << "Enter a number between 1 and 100 (" << 20 - tries << " tries left): ";
std::cin >> guess;
std::cin.ignore();

if(tries >= 20) {
break;
}

if(guess > number) {
std::cout << "Too high! Try again.\n";
} else if(guess < number) {
std::cout << "Too low! Try again.\n";
} else {
break;
}

tries++;
}

if(tries >= 20) {
std::cout << "You ran out of tries!\n\n";
} else {
std::cout<<"Congratulations!! " << std::endl;
std::cout<<"You got the right number in " << tries << " tries!\n";
}

while(true) {
std::cout << "Would you like to play again (Y/N)? ";
std::cin >> answer;
std::cin.ignore();

if(answer == 'n' || answer == 'N' || answer == 'y' || answer == 'Y') {
break;
} else {
std::cout << "Please enter \'Y\' or \'N\'...\n";
}
}

if(answer == 'n' || answer == 'N') {
std::cout << "Thank you for playing!";
break;
} else {
std::cout << "\n\n\n";
}
}

std::cout << "\n\nEnter anything to exit. . . ";
std::cin.ignore();
return 0;
}

Now, I want to do two things:
1. I want to change the number of tries from 20 to infinity
2. I want to give the user an option to exit the game by inputting -1.
How can I do this? Thanks a million!

[TarikNeaj]

You can create a boolean. Call it bool option = true;

Then do

while(option == true)

And then an if statement thats something like

if(guess == -1)
{
    option == false;
}

That should run the loop until guess is equal to -1.