i am beginer so i need help

[chan3x]

#include <iostream>

using namespace std;
int main() {

	int i , y = 1 , n = 0;

	cout << " do you weant continu ? y/n : ";
	cin >> i;

	if (i == 1) {
		
		cout << " it is working oooo" << endl;
		
	}


	system("pause");
	return 0;
}

why it does not works ?

I need a program that will finally asks me "want to try again? y/n ? "
P.s : sorry for my broken English

[TarikNeaj]

why it does not works ?

It works exactly how you programmed it =)

If you want it to ask you over and over again until you enter "y" then you'll need a loop - http://www.tutorialspoint.com/cplusplus/cpp_loop_types.htm

Read @MikeyBoys's post.

[MikeyBoy]

You ask the user to enter a character 'y' or 'n'. However, you store that value in an integer, not a char, and you then you compare that value to 1, not to 'y'. Why would the user enter a 1, when you've asked them to enter a 'y' or an 'n'?

Also, on line 6, you've defined two variables, y and n, that you never use. Declaring variables with those names does not somehow magically associate them with the characters 'y' and 'n'.

[tom221b]

You should have asked this question in the beginners forum.

int i , y = 1 , n = 0;
you have not used the variables y and n, so there is no use of them. Also if you are asking the user for a 'y/n' response, i should be of 'char' type, not 'int' type.

if (i == 1)
should be
if (i == 'y')
now if user inputs 'y', the following block is executed

I need a program that will finally asks me "want to try again? y/n ? "

to do that, you need a loop.

[chan3x]

tom221b thenx so much i forgot ' i wrote if ( i == y ) and ofc it was wrong
sorry for my english
thenx all for answers

and it is working well :

int main() {

	char i , y , n;
	
	cout << " do you weant continu ? y/n : ";
	cin >> i;
	
	cout << i << endl;
	if (i == 'y') {
		
		cout << " it is working oooo" << endl;
		
	}


	system("pause");
	return 0;
}