comparing two objects

[bozmin]

I have two object containing the same numbers.
the first object has numbers coming as follow: n1 = 1.2.3.4.5.6.7.8.9.10
and the second object : n2 = 2.6.3.4.8.6.7.9.5.10.1

Is there anyway to compare the two object to see if they are similar or not??

bool operator==(const Numbers& n1, const Numbers& n2){
	
	bool result;
	result = (n1==n2);
      return result;
}

I didn't find a way to reorder the second object to be able to compare theme.

[Zhuge]

You could sort your lists and then compare them element by element. I'd need to see more of your Numbers class to know what it is supposed to be.

[bozmin]

hi, here is a modified and mini version of the code that represent what i want to do ;

TestList.h

#ifndef TESTLIST_H
#define TESTLIST_H
#include <iostream>
#include <list>
using namespace std;

class TestList{
	TestList();
	friend bool operator==(const TestList& l1, const TestList& l2);
};

#endif 

TestList.cpp

#include "TestList.h"
#include <iostream>
#include <list>

TestList::TestList(){}
bool operator==(const TestList& l1, const TestList& l2){
	
	bool result;
	result = (l1==l2); 
	return result;
}

UseTestList.cpp

#include "TestList.h"
#include <list>
#include <iostream>
using namespace std;

int main(){
	bool result;
	int num;
	list<int> list1;
	list<int> list2;

	list1.push_back(3);    list1.push_back(4);
	list1.push_back(10);  list1.push_back(15);
	list1.push_back(43);
	
	list2.push_back(10);  list2.push_back(43);
	list2.push_back(15);  list2.push_back(3);
	list2.push_back(4);
	
	cout<<"\tlist1: ";
	for(list<int>::const_iterator it1 = list1.begin(); it1 != list1.end(); it1++)
		cout<<*it1<<".";
	cout<<endl;
	
        cout<<"\tlist2: ";
	for(list<int>::const_iterator it2 = list2.begin(); it2 != list2.end(); it2++)
		cout<<*it2<<".";
	cout<<endl;

	result = operator==(list1, list2);
	cout<<"Compare Result : "<<result<<endl;
	
	return 0; 
}

The two list are the same, but the second one is not ordered
I d like to reorder the second list to make to similar to the first one.

[bozmin]

Sometimes the answer is so simple that i really don't get how i missed it .
The only think i had to so is add:
list2.sort();
well. thank you for the help

[AbstractionAnon]

I don't think your code is doing what you're expecting.

Line 30: You're calling operator == and passing list1 and list2. Both list1 and list2 are of type list<int>. That's going to call std::relational operator ==, not your function in testlist.cpp because the signatures are different. Your operator == (.cpp line 6) is expecting two arguments of type TestList&, not list<int>.
http://www.cplusplus.com/reference/list/list/operators/

BTW, if you were to actually call your operator ==, it would result in infinite recursion and a program crash. How do you think line 9 is going to be evaluated? That will result in a recursive call to your operator==, which results in another call to it, ad nauseum.