HELP! Please :/

thank you!
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Use a for loop.
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for( int i = 0; i < num; i++ ) {
    // ...
}



Also, how do I do this? ------->
Various invalid and valid numbers No matter how many invalid numbers you enter your program should run with 5 valid input values.

Simply decrement counter whenever you get an invalid number.
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counter++;
if ((num > 10) || (num < 1))
{
	cout << "That is an invalid number.";
	cout << endl;
        counter--;
}
Last edited on
Do you mean that the program should ask for a valid number and, if the number entered is valid, print out that amount of $s and then exit after the 5th time?
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I understood that, the part that threw me for a loop (pun intended) was:
asm103940 wrote:
Also, how do I do this? ------->
Various invalid and valid numbers No matter how many invalid numbers you enter your program should run with 5 valid input values.
I think the OP is supposed to ask for a number of $s to output 5 times and then exit the program as opposed to just ask/output once (original code seems to attempt this).
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