C++

Forum

 
Need help on calling objects and parameter objects

kikiyox77 (50)
So for say I have a function called commonType. In my main.cpp file there is a call and it looks like this:
pokemon1.commonType(pokemon2)

Now I am confused as what to do. I am suppose to compare the types the pokemon has and if the have a common type, I would print out yes and if not, it would be no.

so I am stuck since the error says cannot convert:
'bool Pokemon::commonType(Pokemon &)' : cannot convert 'this' pointer from 'const Pokemon' to 'Pokemon &'

this is my pokemon.cpp file
1
2
3
4
5
6
7
8
9
10
11
12
13
 
bool Pokemon::commonType(const Pokemon& pokemon2)
{
	if (type1 == pokemon2.type1)
		return true;
	else if (type1 == pokemon2.type2)
		return true;
	else if (type2 == pokemon2.type1)
		return true;
	else if (type2 == pokemon2.type2)
		return true;
	else
		return false;
}



and this is the main.cpp file that has that method:

1
2
3
4
5
6
7
8
9
 
void test(const Pokemon& pokemon1, const Pokemon& pokemon2)
{
	pokemon1.print();
	cout << endl;
	pokemon2.print();
	cout << "\n    Common type? "
		<< ((pokemon1.commonType(pokemon2)) ? "Yes" : "No");
	cout << "\n------------------------------\n";
}
Last edited on
coder777 (8439)
Add the const qualifier to the function commonType(...):
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
 
class Pokemon
{
...
  commonType(const Pokemon& pokemon2) const
...
};
...
bool Pokemon::commonType(const Pokemon& pokemon2) const
{
	if (type1 == pokemon2.type1)
		return true;
	else if (type1 == pokemon2.type2)
		return true;
	else if (type2 == pokemon2.type1)
		return true;
	else if (type2 == pokemon2.type2)
		return true;
	else
		return false;
}
kikiyox77 (50)
Ah, I see. Thank you. It works perfectly now
Topic archived. No new replies allowed.