even and odd digits in an integer

[marcosivan1994]

could someone tell me how can I separate digits from an integer and determine if the digits are even, odd or zero?

[SamuelAdams]

personally I would convert to a string and check each to see if they are 1, 3, 5, 7, or 9, else they are even.

[goldenchicken]

1. Convert to a string
2.Loop through string
2a. Convert this character to string
2b. Convert that string to an integer ( std::atoi )
2c. If int % 2 == 0 -> even character

[JLBorges]

#include <iostream>

int main()
{
    unsigned int number = 70489026 ;

    do
    {
        const int last_digit = number % 10 ;
        std::cout << last_digit << ' ' ;

        if( last_digit == 0 ) std::cout << "zero\n" ;
        else if( last_digit%2 == 0 ) std::cout << "even\n" ;
        else std::cout << "odd\n" ;

        number /= 10 ;
    }
    while( number != 0 ) ;
}

[lastchance]

#include <iostream>
using namespace std;

void classify( int n )
{
   if ( !n ) return;
   classify( n / 10 );
   int d = n % 10;
   cout << d << ": " << ( d == 0 ? "Zero" : ( d % 2 ? "Odd" : "Even (and not zero)" ) ) << endl;
}

int main()
{
   classify( 12345600 );
}