getchar double number

[GhooSe]

Guys I've written something but ı still lacking

QUESTİON :Write a program that only uses getchar() for input, and can input a double number. You can use printf() to print the integer and confirm it was read in correctly. Assume the number is positive.

Solution ways : 1-) You should include the ‘.’ character before the rational part.
2-) Rationalizing the input character data needs extra arithmetic process, that is, reciprocalization !
Important: You should merge your reciprocaling operator process in looping just after the getchar() of ‘.’


my code :

#include <stdio.h>
int main() {
    int i = 0;
    char num;

    printf("enter the number : ");

    while ((num = getchar()) != '\n') {
        if (num > '9' || num < '0')
            continue; 
       {
		 i *= 10;
        i += num - '0'; }
    }

    printf("entered number: %d\n", i);
    return 0;
}

code doesn't make dot-like conversions

The answer can be like this:
https://i.hizliresim.com/nQoRAN.png

[GhooSe]

up

[jonnin]

to read in a double you should probably accept chars like -{., depend on locale},e and maybe a few others. you only accept 0-9.

if I type 3.14, what does your program do? How do you fix that?

one way is just to dump the thing into a string, so long as the chars are valid, and then use atof to convert it to a double.
if you can't use atof and have to re-create it, you have to divide by powers of 10 after the decimal.

[dhayden]

Once you read the decimal point, exit the loop that enters the integer part and enter a loop that reads the fractional part.

Do you need to handle exponents of 10, like 4.56E10?