### getchar double number

Guys I've written something but ı still lacking

QUESTİON :Write a program that only uses getchar() for input, and can input a double number. You can use printf() to print the integer and confirm it was read in correctly. Assume the number is positive.

Solution ways : 1-) You should include the ‘.’ character before the rational part.
2-) Rationalizing the input character data needs extra arithmetic process, that is, reciprocalization !
Important: You should merge your reciprocaling operator process in looping just after the getchar() of ‘.’

my code :

 ``123456789101112131415161718`` ``````#include int main() { int i = 0; char num; printf("enter the number : "); while ((num = getchar()) != '\n') { if (num > '9' || num < '0') continue; { i *= 10; i += num - '0'; } } printf("entered number: %d\n", i); return 0; }``````

code doesn't make dot-like conversions

The answer can be like this:
https://i.hizliresim.com/nQoRAN.png
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up
to read in a double you should probably accept chars like -{., depend on locale},e and maybe a few others. you only accept 0-9.

if I type 3.14, what does your program do? How do you fix that?

one way is just to dump the thing into a string, so long as the chars are valid, and then use atof to convert it to a double.
if you can't use atof and have to re-create it, you have to divide by powers of 10 after the decimal.
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Once you read the decimal point, exit the loop that enters the integer part and enter a loop that reads the fractional part.

Do you need to handle exponents of 10, like 4.56E10?
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