Convert into a loop

[asy04]

cout << ave1 << endl;
cout << ave2 << endl;

return 0;
}

[salem c]

Exactly how Repeater showed you here.
http://www.cplusplus.com/forum/general/251954/

[salem c]

OP's original post for reference.

 #include<iostream>

using namespace std;

int main(){

int subject[2][3] = { {90,96,95}, {98,90,91} };


\\how to convert this using a loop:
float ave1 = (subject[0][0] + subject[0][1] + subject[0][2]) / 3.0f;
float ave2 = (subject[1][0] + subject[1][1] + subject[1][2]) / 3.0f;


cout << ave1 << endl;
cout << ave2 << endl;

return 0;
}

If you keep deleting your posts after you have your answer, expect people to not bother helping you.