lost in processing .

[Reem Alnuaimi]

Write a program in C++ that reads integer values continuously until zero or negative value is entered. Then program should displays information about each value as follows:
v1 ==> Avg. Of Even Digits: d.dd, Largest Digit: d
v2 ==> Avg. Of Even Digits: d.dd, Largest Digit: d ... etc.

The program should use the following functions:
getAvgEvenDigits( ): a function that takes one value and returns the average of even digits.getMaxDigit( ): a function that takes one value and returns the maximum digit of the value.

#include<iostream >
using namespace std;

int GetAvgEvenDigit(int );
int GetMaxDigit(int );

int main()

 {

int n,x,y,m,v;

do{

cout<<"Enter only (+ve) numbers until zero or negative number is entered \n";
   cin>>n;

}while(n>0);

v=GetAvgEvenDigit(x);

m=GetMaxDigit(y);


cout<<"avg of even digit "<<x<<" is = "<<v;
cout<<" , largest digit  of "<<y<<" is = "<<m;


return 0;
}

int GetAvgEvenDigit(int x )
{
int i,count,v;

for(i=0;i<=x;i++)
   if(x%2==0)
   {
    count++;
   }
   v=x/count;

return v;

}

int GetMaxDigit(int y )

{
int m;
    if(y>m)
    y=m;

   return m;

} 

[helios]

Do you have a question?

[salem c]

Slow down!
Start learning to write and test as you go.

Step 1.

int main ( ) {
    int x = 12345;
    int v = GetAvgEvenDigit(x);
    cout<<"avg of even digit "<<x<<" is = "<<v;
}

Step 2, add GetMaxDigit() function.

Step 3, add a prompt for x in main.

Step 4, put the prompt in a loop, until x <= 0.

[Reem Alnuaimi]

@helios yes the question is how to operate each function.

[Reem Alnuaimi]

Salim c : I didn’t understand but what i know is that x is my input and it is not only one input i should have group of different x values .
But my sequence is right this is the prototype function Style and this what i’ve learned.

See the display it is v1
V2
Actually i have a pic of the display but idk how to upload it here .. can anyone tell me if the website Allows this somehow.

[Ganado]

What we're saying is you need to start small and grow the program from there.

You are trying to get the digits of a number, and then do further processing on those digits. That is not what either of your existing functions are doing.

Given a number, 12345,
• 12345 % 10 = 5
• 12345 / 10 = 1234

You can see that using % 10 gets the the least-significant digit, and doing / 10 removes that least-significant digit. From this, you can write a loop:

#include <iostream>
#include <string>

using std::cout;

void print_digits(int n)
{
    while (n > 0)
    {
        cout << n % 10 << '\n';   
        n = n / 10;
    }
}

int main()
{
    print_digits(12345);
}

Now that you can separate each of the digits of a number, you should able to determine whether the digit is even, or find the max digit, etc.

[jonnin]

this may be easier if you read the numbers as strings.
you don't have to, but that lets you see each digit a little easier. this is possibly not the intent, but it says 'value' not 'integer' in the spec, and a string can have a value.

[Reem Alnuaimi]

thanks guys I will try to rewrite the code .