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calculator problem........

poolet21 (7)
Ok I will mention as much as faster I can my problem since I don't have enough length character as my program is to big.. So I will post one part of the program (one function and it will be the same for the others ) The program works fine but I want when the user add characters (etx:acbd/?<) at addition number I want to print an error message and ask from the user to enter the correct input.. For example::

********
Addition
******** 
Enter two numbers to addition:
f + f

(the program output::) 


Error input. Please used only number.
Enter two number to addition:

2 + 3

(the program NOW output::)


The total sum of 2 + 3 = 5
The total of sum is now 5

The total sum of f + f = 0
The total of sum is now 5


Why the compiler skip the else statement of error???
I am really confused please if you have any ideas please let me know as soon as possible... My code is below::: 

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void addition()    //function for the addition operation...
{
    string num1,num2;
    double x,y;         //variables of the void

    cout << "**********"<<endl;
    cout << "*Addition*"<<endl;
	cout << "**********"<<endl;  // welcome screen
	cout << "Enter 2 numbers to calculate: "<<endl;
    cin >> num1>>num2;

    x = atof(num1.c_str());
    y = atof(num2.c_str());   //change string to double

    if (num1=="0")  //check the string if is number
    {
   sum+= atof(num1.c_str());  //add the converted string into sum

    }
    else
    	if (num2=="0")   //check the second input
    	{
    	sum+=atof(num2.c_str());  //add the converted string into sum

    	}

    	else
    		if ((x == 0) || (y == 0))  //check if the input is string and prints an error message
    		{
    			cout <<"Error input.Please add only numbers"<<endl;
                cout <<endl;

    			sum = 0.0;  //reset the sum if the input is string or char
                addition(); //call the fnc again for the inputs

    		}

    x = atof(num1.c_str());
    y = atof(num2.c_str());   //confirm the convention of x , y numbers

    total = x + y;  // the program makes the calculation of the to numbers
    sum += total;   // save the value and keep

    cout <<"The total sum of "<<num1<<" + "<<num2<<" = "<<total<<endl;  //prints out the equation
    cout << "The total of sum is now "<<sum<<endl;
    cout <<endl;
}  // end brackets of addition function....
poolet21 (7)
*SOLVED*
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