Where is my error?

[Helegurbann]

I work on C:

#include <stdio.h>
#include <stdlib.h>
int a,b;
int add(){
    return (a+b);
    }
int add_transaction[]={
    add
    };

int main()
{
    if(a==5&&b==6)
  printf("%d%s",add_transaction[0],"\n");
  if(a==1&&b==2)
  printf("%d%s",add_transaction[1],"\n");
  system("PAUSE");	
  return 0;
}

And i take this warning error:

[Warning] initialization makes integer from pointer without a cast 

[hamsterman]

When write add without parentheses somewhere in your code, it evaluates to a function pointer.
It is unclear to me what your code is supposed to do, so I can't say how to fix it (adding '()' on line 8 would remove the warning, although your code has problems apart from that..).

[asrar]

here is the right code

#include <stdio.h>
#include <stdlib.h>
int a,b;
int add(){
return (a+b);
}
int add_transaction[]={
add()
};

int main()
{
if(a==5&&b==6)
printf("%d%s",add_transaction[0],"\n");
if(a==1&&b==2)
printf("%d%s",add_transaction[1],"\n");
system("PAUSE");
return 0;
}

[hamsterman]

@asrar, there isn't much "right" about it...

[asrar]

this code can compile on Dev c++. Please tell me what environment you use for this code. and what you want to do with this code.

[johnbob]

You initialise your array add_transaction[] with only one integer, so its size is one; You are thus out of bonds when accessing add_transaction[1]. Also the initialisation of the array is trying to add up a and b, which are never initialized;

[Helegurbann]

@asrar Thank u for ur think.But it doesn't work:
https://rapidshare.com/files/2240070058/Compile_Error.bmp

[Helegurbann]

#include <stdio.h>
#include <stdlib.h>
int a,b;
int add(){
  return (a+b);
    }
int add_transaction[]={
    add,add
    };

int main()
{
    if(a==5&&b==6)
  printf("%d%s",add_transaction[0],"\n");
  if(a==1&&b==2)
  printf("%d%s",add_transaction[1],"\n");
  system("PAUSE");	
  return 0;
}

This is my revised code.I want to change add values in an array.

[hamsterman]

Couldn't you just paste that one line of error massage? And you never did say what you were trying to do.
Anyway, the quick fix would be to do

//...
int add_transaction[2];

int main()
{
   add_transaction[0] = add();
   add_transaction[1] = add();
   //... 

[SwapnilGhode]

Hey there , you have declared your add_transaction[] array to be holding integers and trying to store int& in it
I mean
"add" gives the address of function where from it starts
and even it's integer value it cannot be stored in integer array . You have to do as follows

int (*add_transaction_array)(void)[2] = { add , add } ; // will work fine , or

That's it !!!

Now "add" will yield int& and our array is now capable of storing address of function having signature
int func_name(void) ;

[Helegurbann]

I given an example.I want to be my array's element item 3,4,5,50,638...
@SwapnilGhode And i tried before ur suggested method.But funcs and arrays doesn't work together.
@hamsterman I don't take an error.But doesn't write numbers in screen:

#include <stdio.h>
#include <stdlib.h>
int a,b;
int add(){
  return (a+b);
    }
int add_transaction[2];

int main()
{
    if(a==5&&b==6){
      add_transaction[0]=add();            
  printf("%d%s",add_transaction[0],"\n");}
  if(a==1&&b==2){
       add_transaction[1]=add();             
  printf("%d%s",add_transaction[1],"\n");}
  system("PAUSE");	
  return 0;
}