Simple Return By Reference Example

[Brody]

Shouldn't this return the same vector and the outputs be equal??

#include <iostream>
#include <string>
#include <stdio.h>
#include <stdlib.h>
#include <vector>

void printVector(const std::vector<float>& vec) {
  std::cout << "located at: " << &vec[0] << std::endl;
  for(int i = 0; i < vec.size(); i++) {
    std::cout << i << ": " << vec[i] << std::endl;
  }
}

std::vector<float>& rVec(std::vector<float>& myVec) {
  return myVec;
}

int main(int argc, char* argv[]) {
  std::vector<float> myVec(4,1);
  std::vector<float> secondVec = rVec(myVec);

  myVec[0] = 3;
  printf("myVec\n");
  printVector(myVec);

  printf("secondVec\n");
  printVector(secondVec);

  return 0;
}

Output:

myVec
located at: 0x604010
0: 3
1: 1
2: 1
3: 1
secondVec
located at: 0x604030
0: 1
1: 1
2: 1
3: 1

Thanks!

[Moschops]

Is secondVec meant to be a reference?

std::vector<float>& secondVec = rVec(myVec);

[Peter87]

secondVec is not a reference.

[Brody]

ooooh, yes just looked up return by reference again. Totally missed that. Thanks for the quick response!