const parameter problem

[ylxin1993]

if i declare a funciotn like

 void func(const int a) {

...
}

when I use the function, do I need to specify variable const, like

const int x;
func(x);

if not, why? is there something like auto convert?

[vlad from moscow]

No you need not. For example

void func(const int a);

int main()
{
   int x = 10;
   func( x );
}

Moreover the following two function declarrations are equivalent and declare the same function

void func(const int a);
void func(int a);

So the following code is valid

#include <iostream>

void func(int a);

int main()
{
   int x = 10;
   func( x );
}

void func(const int a)
{
   std::cout << "a = " << a << std::endl;
}

Here qualificator const means only that inside the body of the function you may not change parameter a that is a local variable of the function.

[ylxin1993]

thanks a lot

qualificator const means only that inside the body of the function you may not change parameter a that is a local variable of the function.