Timer and other problems...

[Darkmaster]

maybe you should listen to coder777 and me and use seconds and a for loop.
if you still want to print the minutes and hours, you can use the modulo operator "%"

[Xyexs]

Im sorry... i do not know anything about anything of what you said.... still learnin'

[coder777]

look at this:

int amount_sec = 0;
	if (secminhour=="seconds")
	{
		amount_sec = amount;
	}
	else if (secminhour=="minutes")
	{
		amount_sec = amount * 60;
	}
	else if (secminhour=="hours")
	{
		amount_sec = amount * 60 * 60;
	}
	else
	{
		cout<<"ERROR!";
	}

	for(int i = 0; i < amount_sec; ++i)
	{
		cout<<hours<<":"<<minutes<<":"<<seconds<<endl;
		seconds=seconds+1;
		if (seconds==60)
		{
			seconds=0;
			minutes=minutes+1;
		}
		if (minutes==60)
		{
			minutes=0;
			hours=hours+1;
		}
		Sleep(1000);
	}

[Xyexs]

Will someone translate into english please :D add some comments or something

[Darkmaster]

what excactly do you not understand?

maybe this helps you http://www.cplusplus.com/doc/tutorial/control/

scroll down till you reach loops

[Xyexs]

What i do not understand:
for loop
modulo operator %


i give up... ill take an easier task...

[coder777]

you do not need the modulo operator %

the for loop can be expressed as a while loop:
This
for(int i = 0; i < amount_sec; ++i)

can be replaced with this:

int sec = 0;
while( sec < amount_sec)
{
...
sec = sec + 1;
}

As you can see: the for loop is just a convenient syntax

i give up

if you give up that quick you won't get far...

[Darkmaster]

if you have problems with the loops. try to set up an 10 elements array and print each element with a for, a while and a do while loop.
it will give you an idea how to change them to receive the same result.

the mudulo operator returns the rest of an integer division
so 5 % 2 is 1, since 5 - (2*2) = 1

[Xyexs]

the problem is, im 13 years old and my native language is not english so im having problems learning stuff in english...