while loop - 2 conditions with OR

[IronmanCro]

hi guyz, i have a problem with a while/do while loop, and i'm not certant is it really a problem or i just dont know the rule about using it.
For instance, is it possible to use 2 or more conditions in while loop using ||(or) operator?

int a = 2;
int b = 2;

while(a != 1 || b != 1)
{
do something
a = 1;
}

it doesn't end, it continuesly loops

any thoughts?

Much abliged

[rmxhaha]

Yeah offcourse...

"or" means that if one condition is still true then the whole condition is true

You need to have it false in both condition

so if you set a to 1 and b is still not 1 then it will still loop

[jaded7]

This is because the while condition resolves like this:

if a IS NOT equal to 1
or if b is NOT equal to 1

This means that to terminate that loop, a must equal 1 and b must equal 1. You might want to try using the (and) && operator. For example...

while(a != 1 && b != 1)

Means that a AND b must not equal one for the expression to be true.

[vajahat]

the correct syntax for a do-while loop is
do
{
//your codes here
}while(condition);

furthermore, it is possible to use more than one condition in the while loop by using the || operator but you must take care that if any condition gets true the it will continue to loop and in your code it is clearly visible that the condition "b!=1" is always true as there isn't any statement to change the value of 'b'. So it is an infinite or never ending loop.

[IronmanCro]

Thank you guyz so much, that really clears it up for me. Now when i get it i don't see why did i go with OR hehe. cheers