| Jayaganesh (4) | |
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Hi All, Here is another problem which i have tried to decoded and land up with the same problem of "Time exceeded" . as i am a beginer , i am not able to debug the same inspite of tried the same for one full day. Every time the same error appears . Please help me in understanding and correcting the error in my code. Problem 2: Find the Permutation, (Tanmoy Chakraborty, Indraneel Mukherjee, CMI) A permutation of the numbers 1, ..., N is a rearrangment of these numbers. For example 2 4 5 1 7 6 3 8 is a permutation of 1,2, ..., 8. Of course, 1 2 3 4 5 6 7 8 is also a permutation of 1, 2, ..., 8. Associated with each permutation of N is a special sequence of positive integers of length N called its inversion sequence. The ith element of this sequence is the number of numbers j that are strictly less than i and appear to the right of i in this permutation. For the permutation 2 4 5 1 7 6 3 8 the inversion sequence is 0 1 0 2 2 1 2 0 The 2nd element is 1 because 1 is strictly less than 2 and it appears to the right of 2 in this permutation. Similarly, the 5th element is 2 since 1 and 3 are strictly less than 5 but appear to the right of 5 in this permutation and so on. As another example, the inversion sequence of the permutation 8 7 6 5 4 3 2 1 is 0 1 2 3 4 5 6 7 In this problem, you will be given the inversion sequence of some permutation. Your task is to reconstruct the permutation from this sequence. Input format The first line consists of a single integer N. The following line contains N integers, describing an inversion sequence. Output format A single line with N integers describing a permutation of 1, 2, ..., N whose inversion sequence is the given input sequence. Test Data: You may assume that N ≤ 100000. You may further assume that in at least 50% of the inputs N ≤ 8000. Example: Here are sample inputs and outputs corresponding to the example discussed above. Sample Input 1 8 0 1 0 2 2 1 2 0 Sample Output 1 2 4 5 1 7 6 3 8 Sample Input 2 8 0 1 2 3 4 5 6 7 Sample Output 2 8 7 6 5 4 3 2 1 CPU Timelimit: 3 seconds Memory limit: 64M Grading style: ioi [b]Solution : #include<stdio.h> #include<iostream> using namespace std; int main() { int n; int a[8000],b[8000]; cin>>n; int i,j,count; for(i=0;i<n;i++) {cin>>a[i]; b[i]=0; } for(i=n-1;i>-1;i--) {count=a[i]; for(j=n-1;j>-1;j++) {if(i+1>b[j]) {if(count=0) {b[j]=i+1;} else {count--;} } } } for(i=0;i<n;i++) {cout<<b[i];} } | |
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