### mathematical question

This is the formula for the equation....

Result = 1+ 2!/((x-2))-3!/((x-3))+4!/((x-4) )- … n!/((x-n))

can anyone tell me how to create this program....??
i dont know how to compile it in c++..help me pls
How would you solve it on paper?
^ And that is how you can solve any math problem with c++
Really? I rate C++ akin to a graphing calculator. If you know the features, you can cut out most of the hard work. lol
ResidentBiscuit:yes i have to write the coding on a paper.

the program should ask the user to input 1 integer ....
example the user enters x=3 and n=2
the program will run and print out the answer..
my friends told me that i have to use a for loop and also selection statements..
No Warrenty
 ``12345678910111213141516171819202122232425262728293031323334353637`` ``````#include using namespace std; // n! double f(double x) { if(x > 1) return x * f(x - 1); return 1; } // n!/((x-n)) double fn(double x, double n) { return f(n) / (x - n); } int main(int argc, char *argv[]) { double x = 0; double n = 0; double result = 1; cout << "Enter X = ", cin >> x; cout << "Enter N = ", cin >> n; // Result = 1+ 2!/((x-2))-3!/((x-3))+4!/((x-4) )- … n!/((x-n)) for(int i = 2; i <= n; i++) if(i % 2) result -= fn(x, i); else result += fn(x, i); cout << "Result = " << result << endl; }``````
tq very much santosh reddy the code 100% works for me....i just need to know whats the double f and double fn...
I guess, that will be your homework :)
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