Sort data from txt file into array as its bening read?

[DrolArumil]

Sorry if this is too newb, but no one in beginner responded to me so ill try here.

I am suppose to make a program that reads in data from a text file (integers only) and sorts them as it inserts them into an array of size 10. I did this using an insertion sort, which worked great. But now I am being told that I need the function has to read ALL of the numbers in the text file, not just the first 10, and I am not allowed to store them THEN sort, it has to be sorted as being stored. I cannot figure out how to do this, Any help would be appreciated.

This is what I have for sorting first 10

void sortArray(int iArray[])
{
	string fileName = "";
	fstream inFile;
	int tmp = 0;
	int size = 10;
	
	//Prompt user to input the name of the file
	cout << "please enter file name: ";
	cin >> fileName;

	//Open file
	inFile.open(fileName);
	 int j  = 0;
	//Insertion sort, compares data as its read to the array and swaps numbers if needed
	for (int i = 0; i < size; i++)
	{
		inFile >> tmp;
		iArray[i] = tmp;

		 j = i;

		while (j > 0 && iArray[j-1] > iArray[j])
		{
			swap(iArray[j], iArray[j-1]);
			j--;
		}		
	}

		inFile.close();
}

[SamuelAdams]

How would you do it if you were doing it on paper, or for example sorting pennies by year, one at a time ?

[DrolArumil]

As far as I know, I have to do it one at a time, dont I? can the fstream hold more than more value at a time?

also the numbers are arbitrary, they wont necessarily be 1,2,3,4... it could be 2,5,8,12,15...

and the way the txt file is laid out is like this
1
2
3
4

so each number is a line