Implement the quick sort algorithum using recuesive function

Hello, guys I have written this code to arrange user input array in an order. However, I am not able to figure the error on this code that i have witten pls help me out
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//Recursive Quick Sort
#include<stdio.h>
#define ARRAY_SIZE 10
void quick_sort(int array[], int len)
{
	int a[ARRAY_SIZE], c, d, pos;
	for(c = 0; c<len; c++)
	{
		pos = c;
		for (d = c+1; c <len; d++)
		{
			if(a[pos] > a[d]) // error is in this line
				pos = d;
		}

		if (pos !=c)
		{
			int swap;
			swap = a[c];
			a[c] = a[pos];
			a[pos] = swap;
		}
	}
	printf("Sorted list\n");
	for( c=0; c<len; c++)
	{
		printf("%d\n", a[c]);
	}
}

int main(void)
{
	int array1[ARRAY_SIZE], index,a[ARRAY_SIZE], c, d, pos;
	printf("Enter 10 integer: ");

	for(index = 0; index<ARRAY_SIZE; index++)
	{
		scanf("%d", &array1[index]);

	}


	quick_sort(array1, ARRAY_SIZE);

	getch();
	return 0;
}
What makes you thik that there is an error there?
First I noticed that you passing array bur sorting uninitializated local array a
You are using elements in the a array without initializing them.
it's neither quick sort (instead it's bubblesort) nor recursive.

use array in place of a in your quick_sort() function
@ Miinippa I debugged my code form visual studio and every time i run it value at this line are always negative number....
@coder777 how can i make it recursive. I cant use for loop...
I debugged my code form visual studio and every time i run it value at this line are always negative number....
Of course it will be random number! You are sorting uninitializated local array a

As coder777 says use array instead of a
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