How would I make this into a while loop?

[4wRjE3v7]

#include <iostream>
using namespace std;

int main()
{
    int num;
    cout << "Please enter an integer\n";
    cin >> num;

    if (num ==0)
    {
        cout << "Your integer is zero\n:";
        
    }
else if (num % 2 == 0)
{
    cout << "Your integer number is even\n";
}
    
else
{
    cout << "Your integer is odd\n";
}
    cout << "Thanks for using our integer program!\n";
}

I have to write a program that asks the same thing: for the user to enter a number and keeps a running total of the number of even and odd numbers seen. If the user enters 0, the program should print the total number of even and odd numbers and exit.

[Elidor]

Does this answer your question?

#include <iostream>

int main()
{
    using namespace std;
	
    int num, evens, odds;
	
    cout << "Please enter an integer: ";
    while (cin >> num && num != 0)
    {
        if (num % 2 == 0)
            evens++;
        else
            odds++;

        cout << "Please enter another integer: ";
    }
	
    cout << "You have entered " << evens << 
            << " even numbers and " << odds << 
            << " odd numbers.";
	
    return 0;
}

[Disch]

odds and evens are uninitialized.

[Elidor]

Sorry that was a very amateur oversight.

Replace the declaration in the code with this:
int num, evens = 0, odds = 0;

[4wRjE3v7]

Thanks Elidor:)!!