Problem Displaying Address of Character

[xsesx]

When this programs runs it displays odd symbols for the address of the character. This is only part of the program, I took out the parts that already work. Is this supposed to happen? Any ideas on how to fix it?

#include <iostream>
using namespace std;

char again;

int main()
{
	char character = '8';
	char *ptr2;
	ptr2 = &character;


	do
	{
		cout << "Character" << endl;
		cout << "Value: " << *ptr2 << endl;
		cout << "Address: " << &character << endl;
		cout << "Size: " << sizeof(character) << " bytes" << endl << endl;

		cout << "Do you want to run this program again? Y/N: ";
		cin >> again;

	} while (again == 'y' || again == 'Y');

	return 0;
}

[cire]

cout interprets a char* as a c-string. If it didn't, when you did: cout << "Character" it would print the address of the string.

cout << "Address: " << static_cast<void*>(&character) << endl;

[xsesx]

Ah, I understand now. Thanks for the help!