Setting the value of a pointer from function

[maiko]

I declared a pointer in main with value 0, so I want to change its value so that it points to other variable from a function, I guess the function creates a copy of my pointer that's why whatever I do within function doesn't change the real direction of the pointer in main.
I've been trying something like this:

#include <stdio.h>

void redirectionate(char *str, char *ptrCopy);

int main()
{
    char str[] = "ThiS Is";
    char *ptrcopy = 0;

    redirectionate(str, ptrcopy);
    printf("%p\t%p\n", str, ptrcopy);
    return 0;
}

void redirectionate(char *str, char *ptrcopy)
{
    ptrcopy = str;
}

And the output is:

0xbfe83f24	(nil)

So, please let me know if there's a way to do this.
Thanks.

[Dy7SLyTq]

look up string.h and strcpy

[Smac89]

Uhh, line 11 should be:

printf("%s\t%s\n", str, ptrcopy);

And output should be:

ThiS Is             ThiS Is

[Dy7SLyTq]

I didnt even notice that. thats why its printing out what you had before; it prints out the address of the pointer

[Caligulaminus]

maiko wrote:

I guess the function creates a copy of my pointer

Exactly.

[S G H]

You can try by having a reference-to-pointer o pointer-to-pointer input.

[maiko]

Ok thank you all and especially to EssGeEich, I achieved having the pointer declared in main by passing it as a reference to pointer.

void redirectionate(char *str, char *&ptrcopy);

And the output shows the following:

0xbfb8be44	0xbfb8be44

The same memory address xD thanks

[S G H]

You're Welcome ^^