### Help With String Parsing

I really have no idea why it's not working, but I'm trying to convert a double into a string to count the number of characters. It works, but if I have an umber greater than 999999(has 7 or more numbers) it changes it to an exponent. It doing so messes up the number of characters. I heard string parsing would work, but I don't know how...

 ``1234567891011121314151617181920212223242526272829303132333435363738394041424344`` ``````void getVarLengths(double number1, double number2, double number3, int &count1, int &count2, int &count3) { cout << number1 << endl; cout << number2 << endl; cout << number3 << endl; //For large numbers //First so that it doesn't put them in scientific form if (number3 > 999999) cout << fixed << setprecision(7); if (number3 > 9999999) cout << fixed << setprecision(8); if (number3 > 99999999) cout << fixed << setprecision(9); if (number3 > 999999999) cout << fixed << setprecision(10); //Declare variables ostringstream sstream1; //I think this is another way to declare a variable sstream1 << number1; //Put the number into the ostringstream variable string first = sstream1.str(); //And then that into a regular string ostringstream sstream2; //Same sstream2 << number2; //Put the number into the ostringstream variable string second = sstream2.str(); //And then that into a regular string ostringstream sstream3; //Same sstream3 << number3; //Put the number into the ostringstream variable string third = sstream3.str(); //And then that into a regular string cout << first << endl; cout << second << endl; cout << third << endl; count1 = first.length(); if (number2 != 0) count2 = second.length(); //End if count3 = third.length(); cout << count1 << endl; cout << count2 << endl; cout << count3 << endl; cout << fixed << setprecision(0); }``````

Some of it really is just for debugging.

Thanks!
Topic archived. No new replies allowed.